Rabu, 01 April 2009

Reflection of Video

1st Video

Inspiration

 On this video, the teacher trying to explain about William Shakespeare, Shakespeare is an artist. He made a lot of creation especially in art. The teacher ask his students to see the world and all things in this world from a different way, we should look something not only from one sides but the other too, so we can see the beauty of things not only the bad side. He wants his students find their own way to creation; he gives an example by stand above a table. And then he gives his students to try it too, it’s not only about what we see from above the table but about how we see something from the other view.

 

2nd Video

Believe

 On the second videos, there is a kid whose gives a speech on opening ceremony. He said if he believes in himself and asked the audience to answer are they believe in him too, the audience was so excited and so enthusiasm to this kid said “yes!”  He talked about a lot of things, and he said “if you believe in me, I can so anything, think anything, say anything, and become anything”. And once again the audience seemed so enthusiastic to it, they never missed to response what the kid does. The kid said that we must believe in our self to build confidence and to be our self. So that if we believe from our heart we can do anything, think anything, say anything, even become anything we want so that that our mind have a very big impact to our life.

 

3rd Video

What’s you Know about Math?

 On the third videos, I realize that math is not only about such a boring thing. We can make mathematics more interesting if we mix it with art. On this video we saw mathematics that being explained by a song. The title of the song is “What’s You Know about Math?” There are two singers on this song, and the sing rap genre. They said that mathematics is about trigonometry, exponent, matrix, multiplied, and so on. From this video I can understand that learn about mathematics it’s not all about something boring and complicated but we can make it more interesting. On the last shoot there is a lecturer whose close the song by saying “I know all about math”.

 

4th Video

Solving Differential Equation

 On this video, I saw how to solving differential equation. If we have dy/dx equals 4 times x to the power of two and we are looking for its differential. We should integrate each side separately, if we integrate dy/dx we will get y and we will get four third times x to the power of three plus C from 4 times x to the power of two. C on this case is constant, that’s why it is infinite identity because of the infinite value of c (constant).

 

5th Video

Solving Algebraic Equation

 On fith video, we are being explained about algebraic equation. There are a lecturer that explained about it. He solved a few questions about it.

 

1.  x minus five equals 3

in this case we are looking for the value of variable x.

x – 5 = 3

first we put additional equation on both sides, in this case we adding five (5) as a additional equation.

 x – 5 + 5 = 3 + 5

And now we can the value of variable x. It is eight (8).

x = 8

 

2.  seven equals four times x minus one

in this case we are looking for the value of variable a.

7 = 4a – 1

We put the additional equation too on in this case, and in this case we put one (1).

1 + 7 = 4a – 1 + 1

So that we get eight equals four times a.

8 = 4a

Then, we must over both sides with four so that we can get the value of variable a. And the result was two (2).

a = 4

 

3.  two thirth times x equals eight

in this case we should find the value of variable x.

2/3x = 8

Now we must times both sides with the oposites of the constanta of variable and the oposite of two thirth is three second.

3/2 . 2/3 x = 8 . 3/2

we get x on the left side and we must over eight with two then times the result with three. Then we can get the value of variable x.

x = 12

 

4.  five minus two times x equals three times x plus one

we must find the value of variable x.

5 – 2x = 3x + 1

First we must put an additional equation on both sides and I adding minus five (-5), so we can get

(-5) + 5 – 2x = 3x + 1 + (- 5)

then we must adding more additional equation with variable x. And we can add minus three times x (-3x)

- 2x = 3x – 4

-2x + (– 3x) =  3x – 4 + (– 3x)

and then we can get minus five times x equals to minus four.

-5x = -4

Now we must over both sides with minus five.

-5x/(-5) = -4/(-5)

so we can get the value of variable x, it is four fifth.

x = 4/5

 

5.  three minus five open bracket two times m minus five close bracket equals minus two

In this case we are looking for the value of variable m.

3 – 5(2m – 5) = -2

First we must times five with two times m minus five. So we can get the full form of it is three minus ten times m plus twenty five equals minus two.

3 – 10m + 25 = -2

We can adding three with minus twenty five on left sides then we get minus ten times m plus minus twenty eight equals minus two

-10m + 28 = -2

Then we put additional equation minus twenty eight (-28)

– 10m + 28 + (-28) = -2 + (-28)

so that we can minus ten times m equals minus tirty

-10m = -30

and we must over both sides with minus ten (-10) so that we can get the value of variable m, it is three

-10m/(-10) = -30/ (-10)

à m = 3

 

6.  a half times x plus a quarter equals one third times x plus five forth

we must find the value of variable x from

½ x + ¼ =  1/3x + 5/4

first we must adding an additional equation and we put minus a quarter (- ¼)

½ x + ¼ + (- ¼) = 1/3x + 5/4 + (- ¼)

so we can get a half times x equals one third times x plus four forth (four forth equals one)

½ x = 1/3x + 1

then we put another aditional equation, now we put minus one third.

½ x + (-1/3x) =  1/3x + 1+ (-1/3x)

and we get one sixth equals one, the last step is multiply both sides by six

1/6x = 1

1/6x . 6 = 1 . 6

x = 6

so we get the value of variable x and it is six

 

7.  oh point thirty five times x minus oh point two equals oh point fifteen times x plus oh point one

in this case we must get the value of variable x

0,35x – 0,2 = 0,15x + 0,1

first we must adding an additional equation and we can adding minus oh point one

0,35x – 0,2 + (-0,1) = 0,15x + 0,1 + (-0,1)

the we get oh point thirty five times x minus oh point three equals oh point fifteen times x, then we adding another additional equation, but now we adding minus oh point fifteen times x. We get

0,35x – 0,3 + (-0,15x) = 0,15x + (-0,15x)

à 0,20x – 0,3 = 0

and we adding oh point three, then we over both sides by oh point twenty

0,20x – 0,3 + 0,3 = 0 + 0,3

à 0,20x = 0,3

à 0,20x/0,20 = 0,3/0,20

so x equals one point seventy five

x = 1,75

 

5th Video

Exponen Rule on Logarithm Equation


 On this video we can get the proof of logarithm equation.

We already know some exponent rules, like

x to the power of a times x to the power b equals x to the power of a plus b

x to the power of a over x to the power b equals x to the power of a minus b

x to the power of a in bracet to the power of b equals x to the power of a times b

So we can use these exponent rules to proof some logarithm equations. 

First we can proof about logarithm basic x of a equals be, so we can find the value of a. Then logarithm basic x of open bracket a to the power of B close bracket, we can change it with B times logarithm basic x of open bracket A. After that we can prove that logarithm basic x of A plus logarithm basic x of B equals logarithm basic x open bracket A times B close bracket is equals. And the last we can proof that logarithm basic x of A minus logarithm basic x of B equals logarithm basic x open bracket A over B close bracket is equals.

  

From all these videos I can find some mathematics equations, and we can get the way to solve it too. We can get the way to learn mathematics is not only with a serious condition but we can learn it by interesting way.

  

Sorry for this late posting, unperfect form, and some mistakes in this post, Sir.